• 模拟

/** * @param {number[][]} matrix * @return {number[]} */ var spiralOrder = function(matrix) { 
             let top = 0, left = 0, right = matrix[0].length-1, botton = matrix.length - 1;     let res = [];     while(top <= botton && left <= right) { 
                 for(let i = left; i <= right; i ) { 
                     res.push(matrix[top][i]);         }         for(let i = top   1; i <= botton; i ) { 
                     res.push(matrix[i][right]);         }          if(top != botton && left != right){ 
                     for
       
        (
        let i 
        = right 
        - 
        1
        ; i 
        >= left
        ; i
        --
        ) 
        { 
          res
        .
        push
        (matrix
        [botton
        ]
        [i
        ]
        )
        ; 
        } 
        for
        (
        let i 
        = botton 
        - 
        1
        ; i 
        > top
        ; i
        --
        ) 
        { 
          res
        .
        push
        (matrix
        [i
        ]
        [left
        ]
        )
        ; 
        } 
        } 
        [top
        , left
        , right
        , botton
        ] 
        = 
        [top
        +
        1
        , left
        +
        1
        , right
        -
        1
        , botton
        -
        1
        ]
        ; 
        } 
        return res
        ; 
        }
        ;